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The familiar quantum measurement axiom that the distribution of the result of the "measurement of the observable A" is given by the spectral measure for A relative to the wave function (in the very simplest cases just the absolute squares of the so-called probability amplitudes) is thus obtained.
Consider the spectral measure (E_2).
where Φη (dλ), F η (dλ), f η representative the random spectral measure, spectral measure and broad spectral measure of η(t).
Let the random spectral measure of X t) is Φ X (dλ), and the spectral measure is F X (dλ), the broad spectral measure which also named the spectral measure of absolutely continuous part of F is f X.
part of the spectral measure for the vector δ1.
Let X t), t ∈ R is stationary processes, F (dλ) and Z(dλ) are spectral measure and random spectral measure respectively.
Let E be a spectral measure and (Phi in mathfrak {M}(E,E)).
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It has been conjectured that a frame-spectral measure must be translationally absolutely continuous, which is a criterion describing the local uniformity of a measure on its support.
A finite Borel measure μ in Rd is called a frame-spectral measure if it admits an exponential frame (or Fourier frame) for L2.
If (dnu ) is the H-spectral measure for (A^*varphi ), then (14.6) says that begin{aligned} nu (I) le ||A||_H ||varphi ||^2 |I| end{aligned} (14.9)(where (|cdot |) is Lebesgue measure) for open intervals, I.
There is a corresponding decomposition ({mathcal H}= {mathcal H}_{ac}(H oplus {mathcal H}_{sc}(H oplus {mathcal H}_{pp}(H)) where ({mathcal H}_{y}) is the set of those vectors, (varphi ), whose H-spectral measure is purely of type y.
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