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Exact(6)

So Eq. (4.8) has no root with modulus one for all (tau>0).

So (2.10) has no root with modulus one for all (tau>0).

(i) If (cu_{ast}<1), from Lemmas 1 and 2, we know that (2.10) has no root with modulus one for all (tau>0).

For any step-size h, if (cu_{ast}<1), then (2.10) has no root with modulus one for all (tau>0).

For any step-size h, if (frac{1-alpha}{alpha c}< bu_{ast}<2+frac{1-alpha}{alpha c}), then Eq. (4.8) has no root with modulus one for all (tau>0).

(1) If (frac{1-alpha}{alpha c}< bu_{ast}<2+frac{1-alpha}{alpha c}), from Lemmas 2 and 3 we know that Eq. (4.8) has no root with modulus one for all (tau>0).

Similar(54)

The authors found that there were two types of cells which differed in Young's modulus: one type had a Young's modulus of 5.6 ± 3.5 kPa, while others had one of 1.5 ± 0.76 kPa.

All roots of (2.10) have modulus less than one for sufficiently small (tau>0).

Applying Corollary 2.4 in [20], all roots of (2.10) have modulus less than one for all (tau>0).

Applying Corollary 2.4 in [20], all roots of Eq. (4.8) have modulus less than one for all (tau>0).

If (bu_{ast}>frac{1-alpha}{alpha c}), then all roots of Eq. (4.8) have modulus less than one for sufficiently small (tau>0).

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