Sentence examples for intersection patterns from inspiring English sources

The work of [ 9] completely characterized the sets of pairwise compatible 3-state characters by the existence of one of four forbidden intersection patterns.

To find a realizable tree structure for a character α, the algorithm examines the pairwise intersection patterns of α with every other character β∈∈c C, and applies the following rules to rule out possible tree structures for α.

Lam, Gusfield, and Sridhar [ 9] recently established that f(3)=3, and they completely characterized the sets of pairwise compatible 3-state characters by the existence of one of four forbidden intersection patterns.

In [ 9], it was also shown that we can determine the compatibility of a pairwise compatible set C of three-state characters by testing the intersection patterns of C for the existence of one of a set of four forbidden patterns.

Structural fractures in the Ordos Basin were developed in multiple orientations under different stress fields, primarily in the Late Mesozoic and the Cenozoic episodes, and this intersection pattern will contribute to wider opening and better connectivity of the fractures.

So we have that the intersection pattern of β and α matches Rule 2 with β2 as witness, and the intersection pattern of β and γ matches Rule 2 with β1 as witness.

Cell arrangement was quantified by examination of cell intersection pattern in the thick ascending limb of the Henle's loop.

We then completely characterize the sets of pairwise compatible 3-state characters by a single forbidden intersection pattern.

Cell-cell intersection pattern was significantly altered in the mutant with increased 4-lateral intersections in contrast to predominantly 3-lateral intersections in the control (Fig. 4F,G).

We give an independent proof of this result and completely characterize the sets of pairwise compatible 3-state characters by a single forbidden intersection pattern.

Then, the intersection pattern of α and β matches Rule 2 with respect to both α i and α j, and so the theorem holds.