Sentence examples similar to well defined self from inspiring English sources

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Indeed, if we had a well defined self-adjoint operator canonically commuting with angular momentum, we would end up with a well-known complex equation defining minimal uncertainty states [21], while in this case we have two such equations, whose solutions provide CR function functions on the R 2 × S 1 for two noncompatible almost complex structures [26].

These endogenous (mostly polyclonal human) antibodies have a broad spectrum of activity against non-immune immunoglobulins from several species, as well as reactivity towards poorly defined (self) antigens.

This change is driven primarily by the shift from highly integrated, dedicated research missions on platforms with well defined processes to self contained experiments with stand alone operations on platforms which are being concurrently designed.

The endonuclease containing region is well characterized with a clearly defined self-sufficient domain [26], [40].

The components of self-monitoring interventions are not well defined despite current guidelines for self-monitoring in cardiovascular disease management.

Gluten sensitivity (the catchall disorder that leads many Americans to abstain from gluten) is not well defined, and most people who self-diagnose don't meet the criteria.

Mechanisms through which cognitive impairment affects self-care are not currently well defined but evidence from other patient populations suggests that self-efficacy, or task-specific confidence, mediates the relationship between cognitive functioning and patient behaviors such as self-care.

Mouse embryonic stem cells (ESCs) provide a tractable system for dissecting this process because intrinsic and extrinsic signals regulating self-renewal are reasonably well defined.

Now, at 23, her message is defined: self-love.

The movie industry's self-congratulatory season is typically well defined by now, with favorites firmly established and potential dark horses looming.

Motivating question: is it true that for potentials V, for which self-adjoint Schrödinger operator is well defined, the property of unique continuation holds?

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