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Assuming now that S and S ′ are conjugate by an element in G ( R ) we obtained immediately that the D –submodule L in V is isomorphic to one of the components of V = D ⊕ D, in particular L is free – a contradiction.
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So, we obtain immediately the following theorem.
We obtain immediately (q=0) and (p=0).
We obtain immediately the following remark.
From this we obtain immediately equation (5).
By (3.8), we obtain immediately that (3.9).
Hence we obtain immediately that the set is bounded.
So, following M/D/1 queue analysis [18], we obtain immediately, (4).
Applying Theorem 2.1 with δk + 1= 0, and remarking that Bθ ∈ Θ, we obtain immediately (a).
Substituting for, and, in the equation for, we obtain immediately that for and by assumption.
When (lambda=0) or (mu=0), from Theorem 3.1, we obtain immediately the following result.
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com