Sentence examples for w is large from inspiring English sources

The small value of D is also reasonable for such a function, because when W is large, a small D is a must in order to benefit from the advantages of W < 1/D (see Additional file 1 for a more detailed explanation).

Concerning Proposition B.2, let us add one more remark about the particular case (W = (mathbf{Z }/ hmathbf{Z }) wr mathbf{Z }), with (h ge 2): it is known that any finitely presented cover of (W) is large [21, Section IV.3, Theorem 7].

the value of W is large; net losses, L− R, are small (i.e., less negative); and/or the survival rate advantage of aspens compared with burned pine is large (i.e., right-hand side is more negative).

Instead, there are only few base pairs that are likely to form and that cover v, w, especially for v, w where the internal distance of v, w is large enough such that an outside path has to be considered at all.

In this case, Eq.  8 is more likely to be satisfied and favor choice 1 when: the value of W is large; net losses, L − R, are small (i.e., less negative); and/or the survival rate advantage of aspens compared with burned pine is large (i.e., right-hand side is more negative).

From Figure3, it can be seen that the performance improvement for the OBPA scheme is higher when bandwidth W is larger.

For 0.85-μm SiNW solar cells, the Voc with α-Si H deposited at 40 W is larger than its counterpart with α-Si H deposited at 15 W.

Moreover, when λ w is less than a critical value around 70 pkt/s, the WLAN throughput in the scenario 1 is higher than that in the scenario 2 and the reverse is true if λ w is larger than the critical WLAN arrival rate.

The weight (W) is larger as it is closer to the serum sampling year.

We shall show that although the initial and external disturbances from w are large, every perturbed flow v with the energy inequality converges asymptotically to w as ‖v(t)−w(t)‖L2→0, ‖∇v(t)−∇w(t)‖L2=O(t−1/2) as t→∞.

When the channel cross-section is large, i.e., h and w are large, the second term of eq 1 for the contribution of the surface charge goes to zero, and the channel conductivity matches the bulk conductivity.