Sentence examples for vs in terms of from inspiring English sources
This anatomical feature led us to hypothesize a functional segregation within the VS in terms of the regulation of reward-oriented behavior.
Organic mixtures of KW and BW performed much better (max. 520 ml CH4/g VS) in terms of methane yields than the individual substrates alone (max. 220 ml CH4/g VS).
All the adatoms collected from these two sources are finally incorporated into NW growth either through liquid droplet or nucleate directly onto the top of NW, so there is no significant difference between VLS and VS in terms of growth contribution from impinging adatoms.
Acceleration is the rate of change of velocity with respect to time, so that by integration the velocity v in terms of time t is given by v = gt.
This gives the following theorem, which yields a lower bound on δ ( v ) in terms of Ψ ( v ).
MCF-P combined with ART gives almost the same results as PCS-V in terms of customer defection probability, but it reduces the average waiting time significantly.
With ERMT, MCF-P when combined with ART performs better than PCS-V in terms of the customer defection probability and average waiting time.
Step 4: Derive a lower bound for δ ( v ) in terms of Ψ ( v ) by using δ ( v ) ≥ 1 2 ψ ′ ( ϱ ( Ψ ( v ) ) ). Step 5: Using the results of Step 3 and Step 4 find positive constants β and γ, with γ ∈ ( 0, 1 ], such that f ≤ − β Ψ ( v ) 1 − γ.
We can conclude that δ ( v ) ≥ 0 and δ ( v ) = 0 if and only if Ψ ( v ) = 0. Clearly, δ ( v ) and Ψ ( v ) depend only on the eigenvalues λ i ( v ( j ) ) of the symmetric cone v ( j ) for each j, j = 1, …, N. The following theorem gives a lower bound on δ ( v ) in terms of Ψ ( v ), which is precisely the same as its LO counterpart δ ( v ) (cf. Theorem 4.8 in [18]).
These are reported in Table 3, and the normalized distributions of the three most critical features are shown in Figure 3. Spectral flux clearly distinguishes the meta-clusters II from III and IV from V, in terms of the amount of change within the spectra of the sounds used.
Step 2: Calculate the decrease of Ψ ( v ) in terms of δ for the default step size α ˜ from f ≤ − δ 2 ψ ″ ( ρ ( 2 δ ) ). Step 3: Solve the equation ψ ( t ) = s to get ϱ ( s ), the inverse function of ψ ( t ), t ≥ 1.
