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Hence in view of hypothesis (ii), we have (3.13).
In view of hypothesis (H3)(ii), A is weakly sequentially continuous.
In view of hypothesis (H0), we conclude that (m(t) > 0 ).
In view of hypothesis ( H 4 ′ ), it follows that ∥ ∇ w ∥ L 2 ≤ c 1, (21).
for all t ∈ J. Then we can get u 1 = u 2 in view of hypothesis (A0).
Consequently, in view of hypothesis (d), the contractive condition (5) is satisfied with q = γ ( t 2 − t 1 ) 2 8 + δ ( t 2 − t 1 ) 2 < 1.
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Then, in view of hypotheses (H1), (H2), and (H3), we can apply Proposition 2.4 to obtain asymptotical regularity.
In view of hypotheses (C 1) and (C 2), the operator (mathbb{F}) is Lipschitz and satisfies the growth condition given by bigllVert mathbb{F} u,v) bigrrVert leq C_{mathbb{F}} bigllVert (u, v) bigrrVert ^{q_{1}}+M_{mathbb{F}} quad textit{for all } (u,v inmathcal{E}.
GFA is derived from the point of view of the hypothesis theory described above.
Melatonin is secreted in a circadian rhythm, which is interesting in view of the hypothesis that the pineal gland is a vestigial third eye.
In view of the hypothesis of the theorem, we write | x k D m ( f n ⋆ u − f ⋆ u ) ( x ) | = | x k ( D m ( f n − f ) ⋆ u ) ( x ) |. (3.3).
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com