Sentence examples for using the constant c from inspiring English sources

Exact(1)

The weighting values w ij determine the correspondence between two adjacent pixels, using the constant c as a penalty for smoothing the edges in the image.

Similar(58)

We here abstract from the above example, using the constants C for a complex occurrent (e.g. Extraction of Foreign Body from Stomach by Excision) and A1, A2 for atomic occurrents (e.g. Incision of Stomach, Removal of Foreign Body from Stomach).

Throughout this paper, we use the constant C with subscripts to indicate its dependence on the parameters.

Finally, active transport between compartments was described using the constants k active C and k active N where the superscript related to the compartment from which β-catenin was being transported ('C' cytosol-membrane and 'N' nucleus).

These steps are described in detail in the following two subsections using the constant matrix C= [23 37 11 25] as an example when ε 1 and ε ∞ are 2.

The effective genome size (EGS) for each metagenome was estimated according to the method developed by Raes et al. [ 37], using the constants a =18.26, b =3650, and c =0.733.

Additionally, we can obtain Ω(c), the number of prime factors of the constant c, using the MATLAB command 'length(factor(c))'.

All vertebrates use CSR to irreversibly change the constant (C) region of the heavy chain Ig gene, which dictates the antibody tissue distribution and function.

Indeed, notice that assumptions (2.2) and (2.5) of Theorem 2.3 have been used only in the choice of the constant C (see (2.11)) and in the proof of Step 1.

For instance, when simulating the blow-up profiles in Examples 5.2 and 5.3, we choose the monitor function as M=0.5|u|+0.5|u_{x}|+ bigl((x-0)^{2}+0.001 bigr)^{-1/4}+ bigl((x-1)^{2} +0.001 bigr)^{-1/4}+C, (47) where the constant C is used to ensure that enough mesh points are distributed away from the blow-up region.

By assuming { w i j } is diagonal, we have from (3.20) L ~ η ≥ - C n + 1 2 w i i A i i, k l ( x, u, p ¯ ) D k η D l η, ≥ - C + ∑ k ≠ i w i i A i i, i k ( x, u, p ¯ ) D i η D k η + 1 2 w i i A i i, i i ( x, u, p ¯ ) ( D i η ) 2 ≥ - C ( 1 + w i i | D i η | ), (3.21 where condition A3w is used in the second inequality and the constant C depends on Ω, A, B, g 0 and J 1 [ u ].

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