Sentence examples for using a Weibull distribution from inspiring English sources

Exact(14)

Fatigue assessments performed for ships and offshore structures employ a simplified approach in which the stress range distribution is modeled using a Weibull distribution.

Firstly, a model of the effect of PPM actions on the reliability, unavailability, and cost of components, calculated using a Weibull distribution, is established.

To predict the probability distribution of the peak sidelobe levels, distributions of levels were modelled by using a Weibull distribution at each peak in the sidelobe region of the mean squared magnitude of the aperture smoothing function.

The distribution function of wind speed is regularly considered using a Weibull distribution function [40].

Finally, using a Weibull distribution to model failure in cases of incomplete data, specialist knowledge can be used.

In [17], the authors propose a new optimum decoder of watermarks embedded in the DFT coefficients modeled using a Weibull distribution, while Song in [18] proposes a general statistical procedure based on the total efficient score vector for both GGD and Weibull distribution.

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Similar(46)

We used a Weibull distribution, which fit the data better than a normal or lognormal distribution (results not shown).

We use a Weibull distribution as it has the advantage of having both AFT model and proportional hazards model parameterisations [ 19].

A limitation of this work may be that we used a Weibull distribution for our application of the Branson & Whitehead method, and also used a Weibull to generate our simulated data.

Due to the availability of individual patient-level data in our example we were able to use a Weibull distribution to describe time to healing; otherwise, we would have been limited to specifying a uniparametric distribution.

The site selection coefficients are drawn independently from a normalized distribution ρ(f), which is parameterized by its mean f ¯ and a shape parameter κ [we use a Weibull distribution, which has a tail of the form ρ (f ) ∼ exp [ − (f / f ¯ ) κ ] ; see section 6 of supporting information, File S1 for details].

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