Sentence examples for unknown length from inspiring English sources

This recipe yields the unknown length that we are trying to calculate: fifty yards, since 50 × 50 = 2,500.

We call that unknown length of time the "gap," when we'll be on our own, living nearly as if we were in the Stone Age.

But a Commerce Department officer said today that the quasijudicial process leading to that decision was only now completing the period of public debate, with the United States Import Administration still to conduct deliberations of unknown length.

But for an unknown length of time, at least one exit node, based in Russia, has been silently altering programs downloaded through Tor, according to Josh Pitts, a security researcher for Leviathan Security.

The show was conspicuously a gun-jumping affiar because for the thousands of G. I.s the building had been the first lap of a journey of unknown length & destination Where a few seasons ago, there tourists shuffled nakedly about, there were last week, booths decorated with highly colored lithographs of beautiful Carcasonne and Biarritz.

The city's deputy police chief for homeland security, Kathleen Suey, said the man had been staying in the room where the ricin was found for an unknown length of time and was still renting the room when the substance was discovered.

Since he is introduced before Nehemiah, who was governor of the province of Judah from 445 to 433 bc and again, after an interval, for a second term of unknown length, it is sometimes supposed that this was the seventh year of Artaxerxes I (458 bc), though serious difficulties are attached to such a view.

They are released from a variety of cells, circulate in the blood for an unknown length of time and come to rest on endothelial surfaces.

We should think of the players in Axelrod's tournament as operating under the fiction that the games were of unknown length.

where C hj = Cov[ Ph, P j ] is the covariance matrix; D hj = Cov[ Ph, P b ] if h ≠ b and D bj = 0 otherwise; E j = (E[P b ] - E[P j ])/a i if j ≠ b and E b = 1 otherwise; and w is the unknown length-k vector of relative shares for which the system must be solved.

The unknown 'LENGTH' subfield of the SIGNAL is then deduced from the following relationship [1]: begin{aligned} text{LENGTH} &= text{RATE} &quadtimes!! frac{left(T_{text{packet}},-, T_{text{pre}},-, T_{text{SIGNAleft-, lefT_{text{symb}b}/2rightt)right),-, 22}{8}, end{aligned} (20).