Sentence examples for transform cannot be from inspiring English sources

Exact(6)

A Fourier transform cannot be used for this model as there are no infinite limits in the geometry.

Obviously, the algorithms proposed in [3 5, 7], which are based on the traditional beamspace transform, cannot be employed directly for such UCAs.

However, in the technique used in [ 20], one needs first to apply the Laplace transform on the system, following by the ADM, and finally take the inverse Laplace transform to obtain the approximated solutions, which is much time consuming and sometimes can lead to a very difficult situation, for example, if the inverse Laplace transform cannot be obtained.

In the space-variant case, the problem is even more difficult as traditional techniques such as the fast Fourier transform cannot be employed because the convolution kernel is different at each pixel.

However, because of the fractional delay operator z−α the proposed fractional Euler transform cannot be exactly implemented; only a limited implementation by means of infinite impulse response (IIR) digital filter can be achieved using approximation techniques.

In contrast to LADM, the technique does not need any change of space, which sometime can be very difficult situation to handle, for example, in case the inverse Laplace transform cannot be found.

Similar(54)

However, a plasmid's inability to be transformed cannot be fully attributed to genetic incompatibility between itself and its host.

However, models must represent all source-to-sink processes accurately, and emissions of a compound that is completely transformed cannot be derived.

If these problems are not properly recognized, they may lead to the erroneous conclusion that the K K transforms cannot be used to validate impedance data when the imaginary component does not tend to zero as the frequency tends to zero or infinity.

Some transforms cannot be reasonably automated.

The 2D forward DCT in (2) is implemented by first applying a butterfly-based 1D DCT [15] to each row of the residual block, that is, Y=C N X T, followed by the 1D column DCT F=C N Y T. In such an implementation, even if only a few coefficients are predicted as non-zero, the 1D row and column transforms cannot be skipped.

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