Sentence examples for trace on each from inspiring English sources

We show also that, up to a change of scale, there is a unique trace on each of the commutator ideals.

Two flowcharts were traced on each site, one regarding workflow before and one after the introduction of the new technique.

To normalize our results to the crypt longitude, three lines of known length (μm) were traced on each crypt and the PAS-positive pixels determined in this area.

In this work we put forward a new application of the Virtual Element Method combined with the Mortar method for domain decomposition: we exploit the flexibility of the VEM in handling polygonal meshes in order to easily construct meshes conforming to the traces on each fracture, and we resort to the mortar approach in order to "weakly" impose continuity of the solution on intersecting fractures.

By recognizing this characteristic morphology, the user can easily re-initiate tracing on each of the branches with mouse clicks.

The area of the entire knob was traced on each slice and hemisphere using a mouse-driven pointer (see Figure 4).

A cerebellum VOI was traced on each subject's MR image.

The area of each tumor was manually traced on each slice in which the tumor appeared on T2-weighted magnetic resonance images, and multiplied by the slice thickness to determine the volume of the tumor in each slice.

In addition to the total image intensity increase after each correction step, a plot profile was traced on each image to show the normalized intensity and contrast enhancement in a specific region of interest (right column in Fig. 6).

The peripheries of the contralateral and ipsilateral hemispheres were traced on each section by an evaluator blinded to the injury and treatment status of each animal, and the cortical lesion volume was calculated using a calibrated image analysis routine, using the software Neurolucida (National Institutes of Health, Bethesda, MD, USA).

Moreover, we can suppose that (frac{partial y_{varepsilon }}{partialnu}) has zero trace on ∂Ω for each ε small enough, i.e., in view of (5.8) we have: (y_{varepsilon }in H^{1}(Omega)) and (frac{partial y_{varepsilon }}{partialnu}=0) on ∂Ω for each (varepsilon >0).