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This sum decreases monotonically with increasing Z*, guaranteeing a unique value of Z* that satisfies the condition that this sum is equal to the ground area (see above).
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So, there exists a unique q > 0 such that the sum is equal to 2π.
The norm of the sum is equal to, when we add four orthonormal signals.
The cumulant of the sum is equal to the sum of the cumulants if the signals are independent.
This demonstrates a test on the sum of the two coefficients: the hypothesis that the sum is equal to zero is rejected at the 10% significance level.
Next we add up all the numbers we decided to take and if the sum is equal to \(t\) then accept.
We need to calculate the CTCFs of PAM, sine and cosine signals, and to combine them using the following rules: (i) The cumulant of the sum is equal to the sum of the cumulants if the signals are independent.
The summation over arc set (3,j) guarantees that only one of the arcs (3,j) have non-zero flow because the sum is equal to or less than 1.
This was done by summing the differences Δ θ in phase across each of the three sides of the triangle, with all Δ θ converted to a value in the range [− π, π) before contributing the sum. The sum is equal to zero if no PS is present; otherwise, it is equal to ±2 π.
Based on this one-to-one mapping, we can reformulate the penalized maximum likelihood problem (1)–(2) as follows: we want to find non-negative weights θ p for each path p ∈ P which minimize: (3) where the sum is equal to the ℓ 1 -norm | | θ | | 1 because the entries of θ are non-negative.
When the sum is equal to the initial outflow, you have found the payback period.
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Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.

Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com