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This has solutions of the form (a_{n}^{p} = mathrm {e}^{-2 pi i np/N}) so that (nu_{p} = sum_{m} A_{m} mathrm {e}^{2 pi i m p/N}), giving lambda_{p} = frac{epsilon}{N} sum_{m=1}^{N} H' biggl(frac{2pi m}{N} biggr) bigl[mathrm {e}^{2 pi i m p/N}-1 bigr], and the splay state will be stable if (operatorname {Re}(lambda_{p}) < 0) (forall p neq0).
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com