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Exact(6)
This gives p = 1.
This gives p S ( f x, T x ) = 0, which implies that f x ∈ T x and we are done.
This gives (P n, P n ) = c n c n− 1... c 1(P 0, P 0) and (P 0, P 0) is the integral of the weight function p over an appropriate interval.
This gives p = 0.094 and p = 0.57 for the two cases.
This gives P hyp (x > 127; m, n, k) = 0.0083 indicating that such a clustering of periodic genes is unlikely to occur by chance.
This gives p = 1/(1 + I) = 1 + ṅ/ k bn, so we again have for Ẽ: (33) E ˜ = n p = n + n ˙ / k b Interestingly, in this case the error rate is not constant.
Similar(53)
This gave P = 7284 for the number of measurements.
A permutation test for the significance of this relationship gives p < 0.001.
In this case Equation (7) gives p 0≈Pt.
Solving for p gives p = 1/11.
that gives p = 1.
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com