Sentence examples for the same duplicated from inspiring English sources

Exact(14)

However, for the purposes of our experiment, which compares data fusion strategies using the same duplicated data, we do not expect this strategy to influence our recommendations for the preferred matching method.

In addition, five sister pairs (ZmLTPg6/ ZmLTPg11/ ZmLTPg13/ ZmLTPd7/ ZmLTPg13/ ZmLTPg21, ZmLTPd7/ ZmLTPd13 and ZmLTP2.7/ ZmLTP2.9) appeared to be generated from segmental duplication events due to their positions on the same duplicated gene blocks.

In the case of the HSC model, we can find both situations in the same duplicated region, creating a complex pattern of nucleotide variation and LD along the duplicates.

So they looked for the same duplicated genes in different parts of the plant family tree.

It says it will also make it harder for those whose Pages have been shut down for violations to return with new Pages featuring the same, duplicated content by proactively banned other Pages and Groups, in some cases.

The sequence comparison of susceptible alleles showed that the mosquitoes with three different alleles of ace-1 all shared one susceptible sequence (Figure 3), indicating that the mosquitoes contain the same duplicated allele.

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Similar(46)

Eliminating files that have different names but contain the same duplicate materials.

(Note that, throughout, all figures consider the case in which C and A retain the same duplicate. For each case there is an equivalent case in which C and B (but not A) retain the same duplicate).

In this case, it is more likely that X and C retain the same duplicate, and the expected NST internal branch length will be less than d.

For two post-duplication outgroups, the KNST branch length is e2-e1 (if both outgroups retain the same duplicate; Figure 3b,e) or 2d-e2-e1 (if different duplicates are retained; Figure 3c,d).

In the case where the two duplicates' probabilities of retention differ by a factor r, the two duplicates have probabilities 0.5(1±r) along each branch, and, assuming independent loss along each branch, the probability that X and C retain the same duplicate is [0.5(1+r)]2+[0.5(1−r)]2 = 0.5(1+r2), giving an average internal branch length of d-r2 d-e), which is less than d-r2 d-e

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