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An informal argument for Zorn's lemma can be given as follows: Assume that S is closed under unions of chains.
Note that S is compact.
Assume that S is equicontinuous.
Suppose that S is hemicompact.
Suppose that S is continuous.
Suppose that S is nonempty.
Assume that S is ρ-continuous.
It is easy to see that S is nondecreasing.
end{aligned} We see that S is contractive.
Assume that S is equicontinuous at 0 ∈ X.
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That s is classified for a reason.
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Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.

Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com