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But to say that A is consistent means nothing other than that ∼A is not a theorem.
Assume that a is not F.
Assume that A is nonsingular.
Assume that A is complete.
This means that A is continuous.
Finally, we show that A is continuous.
Now, we show that A is additive.
It follows that A is uniformly continuous.
This shows that A is weighted regular.
This implies that A is additive.
It is clear that A is continuous.
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com