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To evaluate the performance of other G6PD tests, the cutoff points for levels of G6PD deficiency were determined as previously described.
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In this test, the cutoff value is different from that in SP800-90B when the window size is 64 because the value is expected to be incorrect on the basis of the calculation written in the footnote on page 35 in SP800-90B [4].
Sensitivity analyses were performed to test the cutoff among the age groups.
Thus, our study data provided an opportunity to test the cutoff of 500 mOsm/kg relative to daily fluid intake.
In contrast to the analysis of EtG and FAEEs in the patients' hair, there are no established and scientifically tested cutoff values for differentiating the mothers' drinking behavior via meconium, and imagining a reliable, scientifically correct, and ethical way to test the cutoff values in pregnant women is hardly possible [ 33].
To test the cutoff for selecting minimum number of SNPs per 10 Kb window for defining SNP-peak regions we calculated the average number of SNPs per 10 Kb window in the entire genome of Gh13 and compared it to the average number of SNPs in the non-peak regions when calling peak regions using a minimum number of 3, 5, 10, 15, and 20 SNPs per 10 Kb.
Estimation of the RTM effect for normally distributed data can be conducted when, at a minimum, the following four parameters are known: the population mean of the pre-test, the population variance of the pre-test, the correlation between the pre-test and post-test, and the cutoff score representing the high-risk group.
The fall-off latency was averaged from three tests, and the cutoff time was 120 s.
In total, there are 4.7 × 107 SNP-SNP tests, and the cutoff p-value after correction is 1.1 × 10-9.
We used the following definitions of positive screening tests: ⩾ASCUS on cytology, ⩾1pg ml−1 HPV DNA on Hybrid Capture II HPV testing, and the cutoff point reported by the trialists using PCR GP5+/6+ HPV testing.
For 265,487 tests, the significance cutoff for an overall probability of 0.05 for type I error can be approximated as 0.05/265,487 = 1.89 × 10−7.
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