Exact(1)
Taking dot product of (4) with F yields ( {mathbf{F}} cdot {mathbf{nabla }}p_{T} = 0 ).
Similar(58)
For instance, the registration companies Registary Pro is taking dot-pro registrations and Neulevel is registering dot-biz endings.
Just take Dots, for example, which ended up spinning out of betaworks as its own game studio.
The decoder's performance was scored by taking the dot product corresponding to the current frame number (correct frame) and dividing it by the summed dot products corresponding to in-correct frame numbers, weighted by distance from the correct frame.
Taking the dot product of equation (107) with v gives The reader should note that the 4-momentum is just (E/c2, p).
A slightly more complex variant is taking the dot product of the two spectra, taking into account peak intensities.
These match values are computed by taking the dot product of each lineup member vector and MEM.
Hence, performing an nD correlation is equivalent to taking the dot product of the 1D FT of matching 1D projections in FRT space.
Taking the dot product of : mk ~\hat{\mathbf{r}} = \mathbf{p }\times \mathbf{L} - \mathbf{A} with itself yields : (mk)^2= A^2+ p^2 L^{2} + 2 \mathbf{L} \cdot (\mathbf{p} \times \mathbf{A}) ~.
Taking the dot product of A with itself yields an equation involving the energy, A^2= m^2 k^2 + 2 m E L^2 \,, which may be rewritten in terms of the eccentricity, : e^{2} - 1= \frac{2L^{2}}{mk^{2}}E ~.
Taking the dot product of A with the position vector 'r' gives the equation : \mathbf{A} \cdot \mathbf{r} = Ar \cos\theta = \mathbf{r} \cdot \left( \mathbf{p} \times \mathbf{L} \right) - mkr where θ is the angle between 'r' and A (Figure 2).
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Justyna Jupowicz-Kozak
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