Sentence examples for t m c from inspiring English sources

Exact(22)

Under this condition, we can rewrite the previous equation removing the time dependence as P = T max - m - T ref - m C d = Δ T m C d (2).

Let S m, T m : C → C be asymptotically nonexpansive mappings, for every m ∈ { 1, 2, …, r }.

Since all eigenvalues have positive real parts, it follows from (11) that y h ( t ) = t M c is continuous on [ 0, 1 ].

The general solution of (5) can be written in the following form: y ( t ) = t M c + t M ∫ 1 t s − M − I f ( s ) d s = t M c + ∫ 1 t ( t s ) M f ( s ) s d s = : y h ( t ) + y p ( t ).

Then we have y h ′ ( t ) = ( t M c ) ′ = M t M − I c, y h ( k ) ( t ) = ( t M c ) ( k ) = M ( M − I ) ⋯ ( M − ( k − 1 ) I ) t M − k I c, k = 1, …, l, and it is easily seen that y h ∈ C l [ 0, 1 ] ∩ C ∞ ( 0, 1 ]. The estimates for higher derivatives of y h follow from (29).

The baseband echo signal can be written as[6] s t ^, t m = ∑ n A n ⋅ u c t ^ - 2 R n t m c ⋅ exp - j 4 π c f c R n t m (14).

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Similar(38)

Function v c(t) is the volume fraction of collagen, which can be expressed as: (7) υ c (t ) = V c (t ) V c (t ) + V m (t ) = M c (t ) / ρ c M c (t ) / ρ c + M m (t ) / ρ m.

Proof Consider the following decompositions of the complexified tangent bundles: C T (S ) = C T c (S ) ⊕ T = T 1, 0 (S ) ⊕ T 0, 1 (S ) ⊕ T, C T (M ) = C T c (M ) ⊕ R = T 1, 0 (M ) ⊕ T 0, 1 (M ) ⊕ R, where T and R are the following transversal subbundles: (1) T is of dimension 1 and corresponds to the "bad" direction; (2) R can have larger dimension.

Since our model assumed that the LV consisted of two constituents (assumption 4), muscle mass were calculated by subtracting collagen mass from the total LV mass as M m t = M t - M c t. Figures 2 showed the temporal profiles of the mass of the total LV, collagen, and myocytes, as well as collagen volume fraction with age.

The operator R being Riesz, Theorem 3.2 implies σ x ( T + R ) = σ x ( T ), where T = M C or M 0 and σ x = σ w or σ b.

Of course Theorem 12 provides that the recurrence equation (4) has a unique solution f T MC 2, c.

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