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Suppose, conversely, that (beta>0).
Suppose conversely that A is a regular monoid and B is a group.
We shall prove that β = 0. Suppose, conversely, that β > 0. Letting n → ∞ in (3.26), we get φ − lim Δ n → β ψ ( Δ n ) < φ , which is a contradiction.
Similar(57)
Conversely, suppose that the stable converse duality holds between (P) and (D).
Conversely, suppose (iv) fails.
Conversely, suppose that and.
Conversely, suppose (iii) holds.
Conversely, suppose λ ∈ E T).
Conversely, suppose that it is not true.
Conversely, suppose that (3.1) holds.
Conversely, suppose that (I_{1}<infty).
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