Sentence examples for summation order. from inspiring English sources

Exact(4)

Note that in the monostatic case any summation order is valid.

end{aligned} Interchanging the summation order and changing by (nrightarrow n+k) on the inner summation index, we get the desired result.

Note that in the bistatic case the summation order is relevant, that is, the first step must be in the azimuth direction.

Substituting these into (20) gives: We can rearrange the summation order: and apply Proposition A.3: Applying Proposition A.4 gives Breaking up the sums over n on the first and third lines depending on whether the node n is internal or external to the motif ψ W gives: Lines 1 and 4 can be immediately recognised as the generating rule (Definition 2.4).

Similar(56)

After rearranging for the summation's order in (3), we can rewrite t r ( k ) as follows: t r ( k ) = 1 N c ∑ m = 0 ς - 1 d m ( k ) ∑ p = 0 G - 1 c p ( k ) ( w ( m + p ς ) × r ) ∗. (4).

While in experiment 1B monocular motion directions opposed each other and prevented thereby an unambiguous binocular motion percept, experiment 1A used spatial summation in order to mask motion direction.

Note that the last line of equation (2), and equation (3), involve the collection of terms, reducing the number of nested summations in order to speed up calculation.

In this regard, IEC/TR 61000-3-13:2008 prescribes a VU emission allocation methodology based on a stochastic approach which uses a general summation law in order to aggregate numerous sources of unbalance to take into account their random variations.

This kind of normalization ensures that after applying CRA, the summation of zero-order Baum-Welch statistics of top R Gaussian components is identical to the summation of zero-order Baum-Welch statistics not applying CRA, this summation also equals to the number of total speaker frames.

Mimetic properties such as skew-symmetry, energy and enstrophy conservations for the semi-discretization are proved for periodic problems using arbitrary high order summation-by-parts operators.

Let,, be the linear space of all -forms with summation over all ordered -tuples,.

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