The phrase 'summation is done' is correct and usable in written English.
It is often used as part of a conclusion to indicate that the speaker or writer has finished summarizing an idea or argument. For example, "After considering all the evidence, it is clear that the defendant acted without malice. Therefore, summation is done and the jury should find the defendant not guilty."
The second summation is done on all classes other than the true class y n.
The final summation is done over the set S, where S is the set of all possible combinations of relay i∈[1,2..,N].
The summation is done for all binding sites in the window with i being the iteration index, n75 is the number of homotypic neighbors (i.e., Crx-Crx, Nrl-Nrl, or Nr2e3-Nr2e3 pairs) within ±75 bp, m75 is the number of heterotypic neighbors (i.e., Crx-Nrl pairs etc).
Thus, c S = ∑ S V w V · c S V, S where summation is done over all basic trees S V) or, equally, over all basic sets V with cardinality higher than or equal to 3. As above, let V0 be the set of all species contained in leaves of all G j.
Under the further assumption that ε comes from a normal distribution, the maximum-likelihood solution for b and r is equivalent to finding the minimum of the Euclidean norm for the deviation of the observed edge lengths from the expected lengths: (1) where the summation for i is done over the ST edges and the summation for k is done over all GTs.
bbody mass index Summation to 100% is done across the table for exercise and total physical activity, respectively.
The Kirchhoff migration is done after doing hyperbolic summation as NMO and stacking.
The force evaluation on every particle is done by mean of direct summation of the contribution of all the other system's particles, avoiding truncation error.
The summation also was done with nondetections assigned the value of the detection level; similar results for the statistical tests were obtained and are not reported here.
In the second step, we sum for every position in the CRS matrix the corresponding elements from H. In principle, this summation can be done by multiplying a suitable sparse matrix with H.
In the case of short distances, the time-consuming computation by summation has to be done.
