Sentence examples for sum of space from inspiring English sources
U is determined from a known yearly sum of space heating demand as follows: U=frac{sum_{i} Q_{text{sh},i}}{sum_{i} Delta T_{text{heat},i}} (13).
U is determined from a known yearly sum of space heating demand as follows: U=frac{sum_{i} Q_{text{sh},i}}{sum_{i} Delta T_{text{heat},i}} (13) The yearly sum Q sh (unit MJ/y) indicated in Equation 13 is determined either by simulation, from literature or energy performance coefficient (EPC) calculation tools which are developed specifically for Dutch houses.
The officers say that McGee-zax stole a large sum of space cash, but no one admits to seeing him, and the officers leave.
Theorem 2.2 (Peirce decomposition Theorem[1]) The space V is the orthogonal direct sum of spaces V ij (i ≤ j).
We prove a decomposition of a shift invariant space into the orthogonal sum of spaces each of which is generated by a quasi orthogonal generator.
Let us define ( x, y ) B ⊕ ψ ̃ D = ( x B, y D ) ψ ̃, x ∈ B, y ∈ D. B ⊕ ψ ̃ D is called ψ ̃ -direct sum of spaces B and D. Using monotonicity of the pseudo-norm.
Our key point is an orthogonal decomposition of A2λ(B2) into a countable sum of infinite dimensional spaces, each one of which can be identified with a differently weighted Bergman space A2μ(D) over the complex unit disk D.
The direct product of vector spaces and the direct sum of vector spaces are two ways of combining an indexed family of vector spaces into a new vector space.
In this case, the maximum diversity of block-fading MIMO-OFDM system is the product of the time diversity and the sum of maximum space diversities in each path.
For the daily sum of the space heating demand, Q sh,i (unit MJ/day), a simple prediction profile for a single household is constructed from the following relation: Q_{text{sh},i}=U Delta T_{text{heat},i} (12).
Rather than state it for pairs with generic position, the theorem says that the space is a direct sum of six spaces, two of the form just given and the other four simultaneous eigenspaces with (Avarphi = lambda varphi,, Bvarphi =kappa varphi ) with (lambda,kappa in {0,1}).
