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First, under the same type of conditions as for the Shannon theorem, the scaling coefficients of a wavelet expansion will determine uniquely the given square-integrable function.
Assume that (v(x)) is a square-integrable function with respect to the shifted Legendre weight function.
The cumulative of a square-integrable function with a single bump would have these properties, and a Gaussian is arguably the simplest choice.
Here the control input g ( t ) is a function of time t; the problem considers any square-integrable function for g ( t ).
Knowing that the spherical harmonics form a complete orthonormal basis over allows the expansion of any square-integrable function (i.e., vMF) as a linear combination of these (4).
end{aligned} (32) Now, suppose that (f(x)) is an arbitrary square-integrable function on the intervals (Omega_{i}) ((i=1,2,ldots,n+1)).
Similar(48)
When the Hilbert space is the space L2(D) of square-integrable functions on a domain D, the quantity: :\varphi_n \varphi_n^\dagger, is an integral operator, and the expression for f can be rewritten as: :f(x) = \sum_{n=1}^\infty \int_D\, \left( \varphi_n (x) \varphi_n^*(\xi \right) f(\xi) \, d \xi.
Let L2 be the Lebesgue space of square-integrable functions on the unit circle.
We construct a family of irreducible unitary representations of the loop affine group of a line (ax+b group) with central extension on the Hilbert space of square-integrable functions with respect to the Wiener measure.
He began with the space of square-integrable functions on the real line.
We denote the space of square-integrable functions over (Omega = -1,1)) by (L^{2}(Omega)).
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com