A simulation of the example is presented in Table 2.
The reason is that, compared with [4, 11, 17], our results not only do not ignore any useful terms in the derivative of Lyapunov-Krasovskii functional but also consider the relationship among h ¯, h ( t ), and h − h ( t ). Figure 1 shows the state response of Example 1 with time delay h ¯ = 1.59, when the initial value is [ − 1 1 ] T. Figure 1 The simulation of the Example 1 for h = 1.59 s.
As a way of illustration, simulations on the example of the unicycle-type mobile robot are presented.
In this study we probe and compare receptor conformational changes caused by biased agonists binding using molecular dynamics (MD) simulations on the example of the available crystal structure of the β2AR active state.
The FDD approach together with FTC scheme developed is then applied in non-linear simulation to the example of faults in the yaw rate sensor of a UAV aircraft (Machan).
The simulation result of the example case indicates that, through the TE11 beam wave interaction under the presented scheme, more than one quarter of the beam energy can be converted to the wave at 612.7 GHz and to heat, dissipated on the waveguide wall, of radius 2.5 cm.
In this section we present some simulation results of the Example 1 with c=1, t=1, and F z)=(|z|−1)+∧N with N=104, which suggest that in the hyperbolic case the conjecture is still likely to be true.
Numerical simulation of the design example is performed through finite-difference time-domain (FDTD) method.
(16) The parameter values used in the simulation of the numeric example.
In the numerical simulation of Example 1, the number of the nodes is fixed as (n =7); the parameters are fixed as (a_{i} =2) ((i =1,ldots,7)), (c_{k} =1), and (d_{k} = c_{k} hat{p}_{k} / hat{m}_{k} ( k =1,ldots, M)); and the adjustment parameter ({alpha=0.5}).
In the numerical simulation of Example 2, the number of the nodes is fixed as (n =7), and it is assumed that there are two clusters in the GRNs, where (a_{i} =2 ( i =1,ldots,7)), (c_{k} =2), (d_{k} = c_{k} hat{S}_{2k} / hat{S}_{1k} ( k =1,ldots, M )); (M =2); (alpha=2.5).
