Your English writing platform
Discover LudwigSuggestions(1)
Exact(1)
For immunoprecipitations, platelets (5 × 10/mL) were pooled from 3 to 6 mice in modified Tyrodes-HEPES buffer containing 10 μM lotrafiban, 10 μM indomethacin, and 2 U/mL apyrase, and stimulated with 10 μg/mL CRP for 90 and 300 seconds with constant stirring at 1200 rpm at 37°C.
Similar(59)
Third, with constant contributions at each generation, the starting conditions influence the speed with which the distribution of admixture tends toward its long-term distribution, but do not predict the qualitative form of this distribution.
For ∖ let be all the same as in Theorem 3.2, be -expanding, be Lipschitz continuous in the first, second and third arguments with constants respectively, and be -relaxed cocoercive with respect to in the first argument, be -cocoercive with respect to in the second argument, be -relaxed Lipschtz with respect to in the third argument.
For ∖ let be all the same as in Theorem 3.2, be Lipschitz continuous in the first, second and third arguments with constants respectively, and be -relaxed cocoercive with respect to in the first argument, be -relaxed Lipschitz with respect to in the second argument, be -relaxed monotone with respect to in the third argument.
It won't be easy at first, but with constant training, it will become second nature.
Let and be mappings such that is -strongly monotone with respect to in the first argument with constant, -monotone with respect to in the second argument, is Lipschitz continuous with constant and and are -hemicontinuous with respect to and in.
Let F : H 1 × H 2 → H 1 be H 1 ( g 1 − m 1 ) -relaxed monotone in the first argument with a constant α 1, Lipschitz continuous in the first and second arguments with constants β 1 and γ 1, respectively.
Let G : H 1 × H 2 → H 2 be H 2 ( g 2 − m 2 ) -relaxed monotone in the second argument with a constant α 2, Lipschitz continuous in the first and second arguments with constants β 2 and γ 2, respectively.
The company is introducing a new canister unit — and not only a canister, but the first canister with constant suction.
(ii the mapping is said to be Lipschitz continuous in the first argument with constant if (210).
Let M2 : E → 2 E be m-accretive mapping, A2 : E × E → E be α2-strong accretive and Lipschitz continuous in the first variable with constant τ2.
Write better and faster with AI suggestions while staying true to your unique style.
Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.

Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com