Sentence examples for satisfy mark from inspiring English sources

Kareiva, in turn, appreciated his boss's insistence on data: "Someone would tell a story — there are a lot of conservation stories and environmental stories — and that wouldn't satisfy Mark, and it wouldn't satisfy me, either".

We do this both for the informed setting (where (vec {Theta }) is known to the decoder) and the universal setting, where (vec {Theta }) is only known to satisfy the marking assumption.

They're a little expensive but may satisfy territorial marking instincts as well as sharpening claws.

In the 36-page judgment, Mrs Justice King, said she was also satisfied that marks on the younger sibling's back and bottom on the day the sibling was admitted to care, which was just after Ellie's death, was "probably with a belt".

Compute refinement indicators μ ¯ ℓ for all τ ∈ T ℓ ∪ E ℓ Γ. Determine set M ℓ ⊆ T ℓ ∪ E ℓ Γ which satisfies Dörfler marking (56).

Generate uniformly refined meshes T ^ ℓ, E ^ ℓ Γ. Compute refinement indicators τ ¯ ℓ for all τ ∈ E ℓ Ω ∪ E ℓ Γ. Determine set M ℓ ⊆ E ℓ Ω ∪ E ℓ Γ which satisfies Dörfler marking (56).

Compute refinement indicators ϱ ¯ ℓ for all τ ∈ E ℓ Ω ∪ E ℓ Γ. Determine set M ℓ ⊆ E ℓ Ω ∪ E ℓ Γ which satisfies Dörfler marking (56).

(i) Compute discrete solution U ℓ ∈ X ℓ. (ii) Compute refinement indicators ϱ ¯ ℓ for all τ ∈ E ℓ Ω ∪ E ℓ Γ. (iii) Determine set M ℓ ⊆ E ℓ Ω ∪ E ℓ Γ which satisfies Dörfler marking (56).

(i) Compute discrete solution U ℓ ∈ X ℓ. (ii) Generate uniformly refined meshes T ^ ℓ, E ^ ℓ Γ. (iii) Compute refinement indicators τ ¯ ℓ for all τ ∈ E ℓ Ω ∪ E ℓ Γ. (iv) Determine set M ℓ ⊆ E ℓ Ω ∪ E ℓ Γ which satisfies Dörfler marking (56).

(i) Generate uniformly refined meshes T ^ ℓ, E ^ ℓ Γ. (ii) Compute discrete solution U ^ ℓ ∈ X ^ ℓ. (iii) Compute refinement indicators μ ¯ ℓ for all τ ∈ T ℓ ∪ E ℓ Γ. (iv) Determine set M ℓ ⊆ T ℓ ∪ E ℓ Γ which satisfies Dörfler marking (56).

For example, suppose 4 out of 10 samples in class 1 and 6 out of 10 samples in class 2 satisfy the condition: Marker 1 has smaller expression value than marker 2. The score for the pair with markers 1 and 2 is 0.2, which is the absolute difference between the two percentages.