Exact(5)
Then there exists a point x ∈ X such that x α ⊂ F x provided that X satisfies the order sequential limit property.
Then C α ( F, g ) ≠ ϕ provided that X satisfies the order sequential limit property and ( F ( X ) ) α ⊆ g ( X ) for each α.
If an ordered fuzzy mapping F : X → W α ( X ) satisfies σ ( r ) p α ( x, F x ) ≤ d ( x, y ) implies D α ( F x, F y ) ≤ r M α ( F ). for all ( x, y ) ∈ ∇, where M α ( F ) = max { d ( x, y ), p α ( x, F x ), p α ( y, F y ) }. Then there exists a point x ∈ X such that x α ⊂ F x provided that X satisfies the order sequential limit property.
Proposition 3.5 If the orbit O of G through 0 ∈ b M verifies T 0 (O ) ⊂ T 0 c (b M ), then it satisfies the order 3 condition.
If the orbit O of G through 0 ∈ b M verifies T 0 (O ) ⊂ T 0 c (b M ), then it satisfies the order 3 condition.
Similar(54)
Particularly, a Banach space equipped with a partial order is called a partially ordered Banach space if the norm of this space induces a natural topology with respect to the given partial order, which satisfies the order-linearity properties (3).
This type of bias could be avoided by using the isotonic regression that satisfies the ordering constraint for the population means.
If the information provided by Microsoft does not satisfy the order, the company will face a fine of 3 million euros a day, backdated to July, Mr. Todd said.
In our setting, a single buyer decides on the order quantity to fill end-customer demand and a single supplier produces to satisfy the order from the buyer as described in the beginning.
An ordered metric space is said to satisfy the order sequential limit property if ( u n, z ) ∈ ∇ for all n, whenever a sequence u n → z and ( u n, u n + 1 ) ∈ ∇ for all n.
Next, we will show that, under the same hypothesis, the orbit O = G ⋅ 0 must satisfy the order 3 condition.
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