Sentence examples for satisfied equation from inspiring English sources

After doing so, the frequent groups are conduct to the association rules and generate the AssociatedGoodPool which contains all frequent groups satisfied Equation 32.

Any subsequence P that satisfied equation (1), where ∪ is the union operator, was defined as a powerful subsequence, and the powerful subsequence dominated its neighbors.

(1) ∪ v ∈ N P N v ⊆ N P ∪ P To identify the powerful subsequences, we examined each subsequence to determine whether it satisfied equation (1).

The only way to solve this would be by imposing that msatisfied (Equation 10).

If the homogeneity assumption can be satisfied, Equation 16 can be written as sum_{i=1}^{n}w_{i}text{cor}left z_{i}, z_{j}right) = text{cor} z_{0}, z_{j}), quad j=1, 2,cdots,n (17).

This iterative approach satisfied equations of motion in all directions/levels while accounting for the nonlinear passive resistance of the ligamentous spine.

end{aligned} Thus, we have begin{aligned} bigl|(Tx)'(t bigr|leqphi_{p}^{-1}Biggl int _{0}^{-1}Biggl int)fbigl(tau,x(tau),x'( tau)bigr),dtau +sum_{i=1}^{infty} overline{I}_{k}bigl(x(t_{k})bigr)Biggr)leq A|x|+B, quadforall tin J. end{aligned} It follows that (2.15) is satisfied and equation (2.16) is easily obtained by (H3).

It is easy to see that condition (2.9) of Theorem 2.3 is not satisfied and hence Equation ( 3.1) has a nonoscillatory solution {x n } = {2 n } → ∞ as n → ∞.

It is easy to see that condition (2.10) of Theorem 2.3 is not satisfied and hence Equation ( 3.2) has a nonoscillatory solution { x n } = 1 2 n → 0 as.

First we know that the following differential equation is satisfied: (3.63).

Then the following equation is satisfied: ϕ ( a ) ′ ϕ ( b ) = κ ( a, b ).