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To repeat: The argument that we should treat Mr. Tsarnaev as an enemy combatant boils down to his religion and his ethnic origin.
Mr. Powell and Ms. Rice did not repeat the argument that many in the administration had made privately in recent weeks -- that Mr. Hussein had chemical "precursors" and biological agents but kept them in nonweaponized form so that they would not arouse the suspicions of United Nations inspectors.
And we can again repeat the argument.
Now, we can repeat the argument used in the last paragraph to get the desired result.
Let (|e|_{1}|omega|_{infty}) replace (|e|_{p}| omega|_{q}) and repeat the argument above.
Let (|H|_{1}|omega|_{infty}) replace (|H|_{q}| omega|_{p}) and repeat the argument above, we can get the corollary.
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Let me repeat the arguments I advanced in the London Evening Standard.
By this we may repeat the arguments leading to (3.22) and prove that (3.22) holds for the case (varrhoin(frac {n-2}{2},frac{n}{2})).
We can now simply repeat the arguments from the proof for Open image in new window to also get the result for Open image in new window □.
in R N. At last, in the case where s = 0, that is, ν i = 0 for all i, we just take Ψ ε ( x ) : = Φ ( ε x ) and A ρ : = B 1 2 ρ and repeat the arguments above.
Now we can repeat the arguments above to conclude that u t h - 1 ∈ H α 2 m, 1 ( Q, ( h + 1 ) γ + σ ) with the estimate (4.2) for k = h -1.
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Since I tried Ludwig back in 2017, I have been constantly using it in both editing and translation. Ever since, I suggest it to my translators at ProSciEditing.

Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com