You calculate how much heat is released in the reaction.
The point at which equilibrium sets in will depend on temperature, if heat is absorbed or released in the reaction.
All the reactions of interest in slow neutron detectors are exoenergetic, meaning that an amount of energy (called the Q-value) is released in the reaction.
I'll know the heat capacity, and what I'll really be calculating is OK, how much heat must have been released in the reaction to make that temperature change happen?
It is that blistering radiation, released in a reaction that takes about a millionth of a second to complete, that makes the light so unearthly, that gives it the strength to burn through photographic paper and wound human eyes.
For example, the form of the potential-energy surface greatly influences whether energy released in a reaction resides in the vibrations of the product molecules or in their kinetic energy of translation.
The heat released in the reaction zones is transported both upstream (by diffusion) and downstream to other portions of the flame.
The rate of energy released (i.e., the power released) in a reaction between two species, a and b, is Pab = nanbfab(T Uab, where na and nb are the density of species a and b in the plasma, respectively, and Uab is the energy released each time a and b undergo a fusion reaction.
The rate of energy released (i.e., the power released) in a reaction between two species, a and b, isPab = nanbfab(T Uab, where na and nb are the density of species a and b in the plasma, respectively, and Uab is the energy released each time a and b undergo a fusion reaction.
