Sentence examples for relation exactly from inspiring English sources

Exact(1)

We also classify completely some cases where we cannot even express complete information (but close to complete), showing that there are exactly two maximal tractable algebras containing the relation, exactly two containing the relation (≺ ≻ m m≤), and exactly three containing the relation (≺ m).

Similar(58)

In this paper, we develop high order interpolants, from any basis that constitutes a partition of unity, which satisfy these integral relations exactly.

By the weakest definition of stability, a set p1,..., pn of star-polynomials is stable if operators a1,..., an which almost satisfy these relations, meaning ||pi a1,..., an)|| ≤ϵ, can be perturbed within C* a1,..., an) to satisfy these relations exactly.

It is also shown that for any given set of yes/no conditions between points in some finite set, there always exist operators on a finite-dimensional Hilbert space such that their commutativity relations exactly satisfy those conditions.

However, there is no clear explanation about what SNOMED CT "concepts" and "relations" exactly stand for.

In the epistemic reading, the non-root modal takes wide scope over the perfect aspect, and in the metaphysical reading, the scope relation is exactly the reverse.

More generally, one may partition the set s - 1 ( v ) into disjoint nonempty subsets, and then impose a (CK2 -type relation CK2 -typeding exactly to those subsets.

An example of the curious properties of this theory is that the ordinals under one membership relation are exactly the regular ordinals while under the other they are longer; this means that the apparent symmetry between the two membership relations breaks!

(In [49], the semigroup V n is denoted V 1, n.) In this situation, Bergman's explicit construction yields that B ( V n, x ) = K ⟨ x 1, …, x n, y 1, …, y n ⟩, with relations given by exactly the same defining relations as given in above, namely, y i x j = δ i, j 1, and ∑ i = 1 n x i y i = 1.

Actually the expressive power of relation algebra is exactly equivalent to first-order logic with just three variables.

Together with the subset ordering as accessibility relation, we obtain exactly what in Kripke-style completeness proofs is known as the canonical model for implicational logic.

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