Sentence examples for rates of a specific from inspiring English sources

Exact(2)

For such users, a reduction in rates of a specific cause of death is usually an important endpoint – for example, detailed sub-causes of maternal mortality.

Reviews on the prevalence rates of a specific disorder or complaints in one region of the upper extremity have been reported elsewhere.

Similar(58)

The use of a disaggregated data is an important feature of our empirical strategy: the undervaluation index (main covariate) is less likely to be determined by the growth rate of a specific manufacturing sector, partially addressing the specification problem that plagues standard cross-country regressions.

The above equation allows us to compute the transmission loss rate of a specific scheduling approach.

Consequently, the application of such models for the bedside analysis of heart rate of a specific patient may be difficult.

This is fundamentally different from most HEP experiments where the rate of a specific physics process is limited by the cross section of that process.

Using multiple logistic regression, the regression analysis was performed at 1 and 5% significance level to find out how the explanatory variable contributes to the occurrence rate of a specific event (explained variable).

It is possible to manipulate the growth of individual facets e.g. via the introduction of tailor-made additives which via changes in the molecular recognition for the different crystal habit faces effect a reduction in the growth rate of a specific face, providing a means for control of the shape as well the size of the final crystalline product.

"An increased rate of a specific cancer among soccer players wouldn't show us what caused the increase, only if one exists," the Washington health department said in a statement.

The main goal of a phase II trial is to evaluate the objective response rate of a specific tumor type to an experimental treatment.

The total rate of a specific matrix is defined as the stationary frequency of 1 (π1) times the gain rate plus the stationary frequency of 0 (π0) times the loss rate.

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