Sentence examples for q center from inspiring English sources

Accenture's CEO William Green recently joked that lots of studying goes on at the Q Center during the day but that at night the real bonding begins with trips to the local bars.

At Accenture, newly-hired consultants from all over the globe descend on St. Charles, Ill., for two weeks at the Q Center, a former women's college that was turned into a training facility.

This year, Wildfang's goal is to double that amount, giving back to causes including the ACLU, Planned Parenthood, Southern Poverty Law Center, the Tegan and Sara Foundation, Q Center, Girls Inc. and The Malala Fund.

The Q Center also condemned the attack.

Tuesday at the Susi Q Center, 380 Third St. just explains.

Stephen Cassell, event organizer and Q Center board member, reportedly "thought of the action plan in the middle of the night and quickly posted the idea on Facebook".

Since f ∈ R 1, we assume that the eigenvalue λ ∈ R. Put exp q ( E c ( q, 4 δ 1 ) ) is an arc I q centered at q. Observe that ( g 1 k ) m = id on exp q ( E c ( q, 4 δ 1 ) ).

Then, by making use of Lemma 2.3, we can construct a diffeomorphism h ∈ U 0 ( f ) C 1 -close to g which has the invariant hyperbolic small arc I q and disk D q, centered at q, contained in Λ h ( U ), where Λ h ( U ) = ⋂ n ∈ Z h n ( U ).

Definition 2 Given a positive and locally integrable function f in R n, we say that f satisfies the reverse Hölder's condition (write this as f ∈ R H ∞ ( R n ) ), if for any cube Q centered at the origin we have 0 < sup x ∈ Q f ( x ) ≤ C 1 | Q | ∫ Q f ( y ) d y.

Let S p ( ρ ( q ) ) be the forward geodesic sphere of radius ρ ( q ) centered at p. Choosing the local g ∇ ρ -orthonormal frame E 1, …, E n − 1 of S p ( ρ ( q ) ) near q, we get local vector fields E 1, …, E n − 1, E n = ∇ ρ by parallel transport along geodesic rays.

Definition 2 Given a positive and locally integrable function f in R n, we say that f satisfies the reverse Hölder condition (write this as f ∈ R H ∞ ( R n ) ) if for any cube Q centered at the origin, we have 0 < sup x ∈ Q f ( x ) ≤ C 1 | Q | ∫ Q f ( y ) d y.