Sentence examples for puncture 1 from inspiring English sources

More importantly, they showed a dramatic reduction in arterial puncture (1% vs. 14%, p < 0.0005) in the simulator-trained group.

The pain experienced by patients can be significant in arterial puncture 1 compared with venous puncture due to the greater innervation of the arterial sites as well as the need to puncture deeper into the skin.

The key benefits from use of ultrasound included reduction in needle puncture time, increased overall success rate (100% versus 94%), reduction in carotid puncture (1% versus 11%), reduction in carotid haematoma (0.4% versus 8.4%), reduction in haemothorax (0% versus 1.7%), decreased pneumothorax (0% versus 2.4%) and reduction in catheter-related infection (10% versus 16%).

Factors significantly associated with severe morbidity were: older age (64 vs. 57 in patients with low morbidity, p=0.04), delayed lumbar puncture (1 day vs. 0 day, p=0.02), delayed acyclovir introduction (2 vs. 0 days, p=0.006), a worse Knaus score (A: 18.8% vs. 81.3%; B+C+D: 66.7% vs. 33.3%, p=0.004) and the presence of red blood cells in the CSF sample (49 cells/μL vs. 0, p=0,0,).

These data are consistent with current evidence that malignant cells are detected in the CSF in 50 70% of patients with neoplastic meningitis by initial lumbar puncture [ 1, 8, 9], a rate that increases with repeated sampling.

A fourth rider in the break, Shelley Olds of the United States, suffered a puncture 30km from the finish, leaving the remaining trio to sort out the medals between them.

Under ultrasound guidance, 50 (62.5%) required 1 single puncture, 25 (31.5%) 2 punctures and the remaining 5 (6.25%) 3 trials.

A midline laparotomy cecum ligation and a single puncture (18-gauge needle) were performed.

Cytology can be negative in up to 40-50% on initial lumbar puncture [2].

Neuraxial anesthesia should be avoided if the skin lesions at the potential site of puncture [2].

LP use and IP approach were associated with more free event puncture (93 vs 87%, p = 0.03).