Sentence examples for positive intersections from inspiring English sources

In this case, the two nullclines can have either no positive intersections, two positive intersections or one positive intersection depending on the parameter values.

If (B_{1}cap A_{2}neqempthenthe twonullclinesnullclines have two positive intersections and (2.4) has two interior steady states.

Observe that if (frac{lambda_{2}-1}{c_{2}}leq u), then the two non-trivial nullclines cannot have any positive intersections and (2.4) has no interior steady state.

If (B_{1}cap and2}=empty=hat{q}d (y=hat{q}_{2}(x)) is not tangent to (y=q_{1}(x)), then the two nullclines have no positive intersections and thus (2.4) has no interior steady state.

Truly positive intersections must be distinguished from false positives (F+), and such F+ must be removed.

A negative slope and a positive intersection with the NS′-axis means that the induced resistance can completely be eliminated with gas sparging.

(a) Since (frac{lambda_{2}-1}{c_{2}}>bandx}) and both nullclines are strictly decreasing, it can easily be shown that the two nullclines have a unique positive intersection (x^), where (u< x^

Hence, from (2.10 - 2.12) we can verify that if (R_{0}>1), then the two curves (G(I)) and (H(I)) have only one positive intersection in ([0,frac{Lambda}{mu}]), which gives only one endemic equilibrium.

Both  oambP-GAL4 and 0104-GAL4 contain γ5-innervating neurons, but the positive intersection does not label them, suggesting that each GAL4 includes unique γ5 neurons: γ5narrow (γ5n) in oambP-GAL4 and γ5broad (γ5b) in 0104-GAL4.

Consider then the graph of (gamma ), ( Gamma _{gamma } subset C times C), and intersect it with the diagonal (Delta subset C times C): their intersection number must be a nonnegative integer, because intersection points of complex subvarieties carry always a positive local intersection multiplicity.

Since both criteria have to be fulfilled for the study being positive, the intersection hypothesis has to be proven.