Sentence examples for pos I from inspiring English sources

By neglecting the terms of proportional to μ m for m ≥ 2, it can be verified that v p pos ( i ) and u p pos ( i ) are recursively computed as follows: v p pos ( i ) = v p ( i ) - μ i t p ( i ), (27) u p pos ( i ) = u p ( i ) - μ i s p ( i ), (28).

where Accuracy value ( q, C ) = ∑ ∀ i ∈ D 1 pos ( i ) (7).

Fitness function F10 F10 ( q, C ) = ∑ ∀ i ∈ D ∑ j = 1 pos ( i ) r arg ii : pos ( ii ) = = j pos ( i ) | D |, (12)  where r argi i pos(i i)==j) returns 1 if the image ii in the j th position of the ranking is relevant, otherwise it returns 0.  Fitness function F3 F3 ( q, C ) = 1 | D | ∑ ∀ i ∈ D ∑ j = pos ( i ) | I | 1 j (4).

Thus, to determine v p pos ( i ), we exploit the recursive relations in Equation 9, at a posteriori time.

Fitness function F7 F7 ( q, C ) = ∑ ∀ i ∈ D k 3 log 10 ( | I | / pos ( i ) ), (9)  where k3 is a user-defined parameter.

Fitness function F9 F9 ( q, C ) = ∑ ∀ i ∈ D k 8 k 9 pos ( i ), (11)  where k8 and k9 are user-defined parameters.

"This is ab-so-lute-ly pos-i-tive-ly wrong!" Ms. Walker boomed.

This distance is an Euclidean distance divided by the mean of the two detection widths: d pos ( z i, z j ) = 2 | | x → i − x → j | | s i + s j (12).

The positive change region pos(X i,X j ) comprises classes that relate to existing links in both bnodes, with the same neighboring nodes, i.e., these classes contain elements representing equivalent links, considering the mapping between bnodes.

I can have a product library, I can have a full POS system, I can do my accounting with this, I can record my cash in this.

If I hear of anyone purchasing this POS then I'll be sure to laugh and point.