Sentence examples for pattern of intersections from inspiring English sources

Exact(1)

By means of the iterative equation Xi = Xi−1 + Bi − Ti, it is possible to automatically reconstruct the complete pattern of intersections between neurites and the concentric rings.

Similar(59)

Comparing O i and C i sheds light on the pattern of intersection of \documentclass[12pt]{minimal} \usepackage{amsmath} \usepackage{wasysym} \usepackage{amsfonts} \usepackage{amssymb} \usepackage{amsbsy} \usepackage{mathrsfs} \usepackage{upgreek} \setlength{\oddsidemargin}{-69pt} \begin{document} $\mathcal {R}_{i}$\end{documentt} R i with the other S−1 irrRAFs.

This involved segmenting raw data, labelling and coding, while searching for patterns of intersection.

Similar patterns of intersection were found when more genes were considered (data not shown), showing increased consistency at high concentrations.

The intersection of these 12 data sets revealed a core pattern of interactions independent of the threshold used (Additionals files 4H and 5).

Assuming that shape outliers in functional data follow a different pattern, the distribution of intersection angles differs.

It follows that we can find such a subgraph in the partition intersection graph of C by testing the intersection pattern of each pair of characters in C[ 10].

So we have that the intersection pattern of β and α matches Rule 2 with β2 as witness, and the intersection pattern of β and γ matches Rule 2 with β1 as witness.

Then, the intersection pattern of α and β matches Rule 2 with respect to both α i and α j, and so the theorem holds.

If α2∩ γ1≠ ∅, then the intersection pattern of α and γ matches Rule 2 with respect to α2, in which case the theorem holds.

There is a β∈∈c C where the intersection pattern of α and β matches Rule 2 with respect to α i. 2. There is a γ∈ C where the intersection pattern of α and γ matches Rule 2 with respect to α j.

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