Sentence examples for otherwise calculated from inspiring English sources

He has been styling hair "since God was a boy," otherwise calculated as 23 years, 13 of them on Broadway.

In addition to electron impact reactions, the present mechanism includes reactions involving vibrationally- and electronically-excited species, dissociative recombination reactions, three-body recombination reactions, charge transfer reactions, and relaxation reactions, taken from the literature where available, and otherwise calculated using published correlations.

This index is otherwise calculated in much the same way as the PSI (Fig. 4).

Enrichment and depletion was otherwise calculated as described above.

The intensity threshold can be supplied either with options or otherwise calculated programmatically based on the mass/intensity distribution profile of the spectrum.

Adequacy of total nutrition included calories from PN and propofol in addition to EN and did not exclude patients with a contradiction to EN but was otherwise calculated the same as the primary outcome.

And though the ECB insists it will not rescue governments from the consequences of their fiscal folly, markets may believe otherwise, calculating that if a country looked like defaulting it would be bailed out somehow.

He wrote, "The cast are equally strong: Quinto brings wry charm to an otherwise calculating character, while Pine powers through his performance in bullish, if not quite Shatner-esque fashion".

And if the diffusion jump out of Gillespie subvolume ν leads into a particle volume, then accordingly a particle is created which obtains the next reaction time t i ν with probability 1/ N i ν and otherwise calculates its time as in Algorithm 1. However as the target subvolume is particle based, no global waiting time is tracked there.

If the average envelope is zero or has only one extrema or zero crossing, go to step 7. Otherwise, calculate [15]: m(t)=m(t -u(t -u12).

Set v = 0 and α(t)  =  r(t); Let m(t)  =  α(t); Determine the local extrema (maximum and minimum) of m(t); Construct the upper and lower envelopes of the extrema using cubic spline functions; Determine the average envelope given by [14]: u(t)=frac{r_u(t)+{r}_l(t)}{2} (11) 6) If the average envelope is zero or has only one extrema or zero crossing, go to step 7. Otherwise, calculate [15]:  .