Sentence examples for orbit length from inspiring English sources

Next, have students research their planets, including their composition, atmosphere, orbit length, presence (or absence) of moons and any additional information, and prepare to present what they've learned during the final building of the model.

The cyclotrons use reverse bending, for orbit length adjustments, and harmonic number jumps to achieve a synchronous acceleration.

In this setup, the tomographic field of view is determined by the orbit length independently of the collimator acceptance angle.

These re-combined time series are then interpolated onto a fixed 90 minute sampling rate to ensure a regular model output regardless of any variations in orbit length over the mission.

The number κ ( x ) encodes so the orbit length of x under the automorphism group A. (2) One can also see this as graded summation of an elementary result in linear algebra (see [29], p.21): if a finite group acts linearly on a finite dimensional vector space V, then dim ( F ) = ( 1 / | A | ) ∑ T ∈ A tr ( T ).

Fig. 6 Coherence length L φ and spin-orbit length L SO as a function of temperature.

On the other side, the spin-orbit length L so is shown to coincide with superconductance coherence length ξ that indicates the spin-orbit origin of superconductivity.

Figure 6 shows that coherence length L ϕ is proportional to T − 0.53 and the spin-orbit length L so to T − 0.45, which is very close to the T − 1/2 dependence expected for the two-dimensional system.

Therefore an orbit of length N of a map f(x) has threshold (s_{text {th}}triangleq L/N), where L is the length of the curve and is obtained from the well-known formula from calculus L=int^{1}_{-1}sqrt{1+[f'(x)]^{2}}dx.

An n-dimensional Boolean network is said to be c-chaotic, for c < 2, if it has a periodic orbit of length at least c n.

Then g j ′ takes the same value on at least two of the vectors x, y, z, and it follows that the range of g j × g j ′ has size at most 3. Since we assumed that there exists a periodic orbit of length at least c n, we must have 3 | J | / 2 2 n − | J | ≥ c n, and the lemma follows by taking logarithms.