Sentence examples for operators in the form of from inspiring English sources

Exact(5)

Louise Ellman, the Labour MP who chairs the transport committee, said the government should "shine a light" on the annual £4bn taxpayer subsidy of the railways to ensure it does not leak to train operators "in the form of unjustified profits".

These responses are normally defined by the appropriate response amplitude operators in the form of response per unit wave height.

The company provides shallow-water drilling and liftboat services to oil and natural gas operators in the form of construction, maintenance and platform intervention, as well as decommissioning services.

In [18], in the class of harmonic functions in a ball, the properties and applications of the operators in the form of δ μ = r ∂ ∂ r + μ, δ μ m = ( r ∂ ∂ r + μ ) m (6).

The investigation of the boundary value problems, concerning the operators in the form of the sum of squares of vector fields fulfilling Hörmander condition, has turned into the subject of several works, see [2 4].

Similar(55)

The full DtN operator, in the form of an infinite series, is exact.

A discontinuity capturing operator in the form of a Noh-type viscosity with artificial heat flux is used to preserve stability and smoothness of the solution in shock regions.

Here μ > 0, r = | x |, x = ( x 1, …, x n ), and r ∂ ∂ r is a differential operator in the form of r ∂ ∂ r = ∑ i = 1 n x i ∂ ∂ x i.

In body-level subsystem, the linear/angular velocity of the slave body follow the first master's position, and the velocity loss caused by the system disturbances is fed back to the operator in the form of haptic force.

The authors consider the impulsive differential equation with Monge-Ampère operator in the form of textstylebegin{cases} ( (u'(t) )^{n} )'=lambda nt^{n-1}f (-u(t) ), quad tin 0,1), tneq t_{k}, k=1, 2, ldots, m, Delta (u' )^{n}|_{t=t_{k}}=lambda I_{k} (-u(t_{k}) ), quad k=1, 2, ldots, m, u'(0)=0, quadquad u(1)=0, end{cases} where λ is a nonnegative parameter and (ngeq1).

Recently Wismer [20] proposed a loss operator to be in the form of L u = τ y − 1 ∂ y − 1 ( ∇ 2 u ) ∂ t y − 1. (2.6).

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