Sentence examples for one of multiplicity from inspiring English sources

In this book, where searing political upheavals like the Lebanese civil war figure but don't dominate, and in an era when almost all we seem to see of the Middle East is terrorism, it's bracing to come upon a work — and a world — that expands our narrow vision, transforming it to one of multiplicity, enchanting it with hope.

Furthermore, λ 1 ( 3 ) = 1, λ 2 ( 3 ) > 1 and 0 < λ 1 ( 1 ) < 1, λ 2 ( 1 ) > 1. Proof In view of Lemma 1, equation (7) has two positive zeros, one of multiplicity one and another one of multiplicity two, which implies statement (a).

(d) If Δ 1 = 0 and Δ 2 ≠ 0, then equation (7) has one pair of conjugate imaginary roots and two real roots, one real root of multiplicity one and other one of multiplicity two.

If Δ 1 = 0 and Δ 2 ≠ 0, then equation (7) has one pair of conjugate imaginary roots and two real roots, one real root of multiplicity one and other one of multiplicity two.

(f.1) If ((Delta_{1}leq0 ), (Delta_{2}geq0)) or ((Delta_{2}leq0), (Delta_{3}> 0)) then equation (18) has no real roots and has two distinct pairs of conjugate imaginary roots one of them is of multiplicity one and the other one of multiplicity two.

If ((Delta_{1}leq0 ), (Delta_{2}geq0)) or ((Delta_{2}leq0), (Delta_{3}> 0)) then equation (18) has no real roots and has two distinct pairs of conjugate imaginary roots one of them is of multiplicity one and the other one of multiplicity two.

(P'(x)) has a multiple one (frac{a^{2}}{3c}) of multiplicity 2. (frac{a^{2}}{3c}) is not the extreme point of (P x)).

Gender is just one of a multiplicity of inequalities that combine to form the patterns of poverty and exclusion that we see in the world today.

While some HIV-1 amino acid changes individually associate with decrease in VL, the compound image that emerges is one of a multiplicity of modest effects distributed across many residues.

Furthermore, the following hold: λ 1 = − 1, λ 2 > 1. Proof In view of (7) and Lemma 1, we have that the function f ˜ ( y ) = y 5 + 2 A 1 y 3 − b 1 2 c 2 y 2 + A 1 2 y − a 2 b 1 2. has one zero y ¯ of multiplicity one.

(e) If Δ 1 = 0 and Δ 2 = 0, then equation (7) has one pair of conjugate imaginary roots and one real root of multiplicity three.  .