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Then, based on previous inequality the following inequality is proven.
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We choose any fixed (thetain 0,pi)) such that (lnrho r, theta)) is absolutely continuous on r, and we integrate the previous inequality on the interval ([1,R]) to get int_{1}^{R}frac{1}{Kr},drleq int_{1}^{R}frac{partial }{partial r}lnrho,drleq int_{1}^{R}frac{K}{r},dr.
Integrating the previous inequality with respect to and on, we have, (3.9).
We first give necessary conditions on the potential V, under which the previous inequality can or cannot be further improved.
On the other hand, if (so ), the previous inequality can be written as (2.9).
On the other hand, we have, and therefore, previous inequality indicates that is complete.
If then and the previous inequality holds.
For, the previous inequality is satisfied.
This inequality, together with the previous inequality of MU3 G < 0.279MO, leads to 0.1905MO < MU3 G < 0.279MO.
Brazil's new government must build on previous efforts to address inequality through the income transfer schemes like the Bolsa Familia.
ML contributed to reviews on previous studies on health inequalities and construction of the socioeconomic variables.
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com