The invariant subspace problem is the question of whether every operator in B ( E ) has a nontrivial invariant subspace.
A Hilbert space operator is called universal (in the sense of Rota) if every operator on the Hilbert space is similar to a multiple of the restriction of the universal operator to one of its invariant subspaces.
"Shall we impanel a new jury for retrial, say, next week?" "The Night Of" reminds us that every operator in the American legal system is compromised, which is why Weiss retains our interest at this late moment, long after she has coached a pathologist into delivering false testimony, and just after declining to pursue late-breaking evidence that might have implicated someone other than Khan.
Every operator of the pipe belt conveyor is able to obtain the required information based on known input values using the corresponding graphs.
"He knew the names of every elevator operator, always asked how their wives were doing," says Earl Friend, who worked on the Kaufmanns' dairy farm at Fallingwater and who benefited directly from the Kaufmanns' largess -- they helped to place and provide for his crippled daughter at a state nursing home.
Fourth, users of landline telephones never knew the exact locations of every switch, operator, relay and transfer station.
I bring all this up because I just flew back from Australia, a country with one-tenth the population of the U.S. Yet the Australian racing industry is the envy of every racetrack operator in the States.
(chi ) is an eigenfunction of every Laplace-Casimir operator D(I).
In that case the character (chi ) of (rho ), which automatically exists, is the trace (mathrm {Tr}, rho ), which is a radial eigenfunction of every Laplace-Casimir operator.
We also show that it is an eigenfunction of every Laplace-Casimir operator D(I) and if (mathrm {dim}, U_0 = mathrm {dim}, U_1 = mathbb {C}^n), i.e., if we are dealing with (mathfrak {g} = mathfrak {osp}_{2n|2n},), then the Laplace-Casimir operators annihilate (chi ^prime ).
