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So, T is not completely continuous.
Now, we prove that the pair ((T,C)) satisfies the condition (BP) and T is not completely continuous.
If the pair ((T,C)) satisfies the condition (BP), then T is not completely continuous in general.
However, if a mapping is not completely continuous, in general, it is difficult to verify that the mapping satisfies the set-contractive condition.
Since (T(C =C) and the unit ball C in infinite dimensional Hilbert space is not sequential compact, it follows that T is not completely continuous.
On the other hand, the linear term with coefficient b could not be implemented in their equation, because it is not completely continuous in (36) below, as required in [13].
Similar(53)
Anyway the system defined as "continuous" is composed of several steps which are not all completely continuous, due to the presence of the malaxer, a device that works in batch.
Although this value is lower than expected on the basis of the binding data alone, it explains why the USP4CD is not completely inhibited in the continuous presence of the insert.
In Theorem 4.1, even though we do not assume that T is completely continuous, even continuous, we can assert that (u_{lambda}) depends continuously on λ.
In Theorem 5.1, even though we do not assume that T is completely continuous or even continuous, we can assert that (u_{lambda}) depends continuously on λ.
In general, a completely continuous operator may not be always compact.
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Justyna Jupowicz-Kozak
CEO of Professional Science Editing for Scientists @ prosciediting.com