Exact(6)
To distinguish the malicious nodes, we will do a quantitative comparison based on the correlation coefficient.
In analyzing the energy consumption of nodes, we will consider only the energy consumed by transmitting.
Proof: (a) For the network ψ which contains k nodes, we will have an area with k equal node cells.
To solve the PA problem for all nodes, we will split the problem into K + 1 subproblems.
Basically, each node is given the task of witnessing for the presence of a specific set of other nodes (we will say that is tracking nodes in ).
While considering the left child and right child for the upper nodes, we will choose the highest priority-based edge as main-Edge and dummy-Edge will be NULL but here if highest priority based edge exist more than one and all of them follow protocol id [1 and 6 both] then we take two edges.
Similar(54)
So every time we enter record node, we will reset all the elements in the note array to zero.
If that is not possible due to the low density of FT-nodes (we will discuss this in Section 4.3), it attempts to keep the connectivity of the backbone network as close to k as possible.
Since we next present the operations performed at each relay node, we will intentionally omit any references to the particular node j.
If there is an existing counterclockwise flow with as its source node, we will start with this flow in the unidirectional packing.
The other is coding update which begins only after receiving an ACK packet from a coding node (we will discuss this ACK process in the following section).
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