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There is no degeneracy for modes.
93.7% of the primers had 4-fold or less, while 71.4% had no degeneracy.
In this set one is remarkable because its first five eigenfrequencies have no degeneracy and are almost exactly harmonic.
In particular, if there is no degeneracy among the eigenvalues of ρUS , these projectors are one-dimensional and ρSS is the one-dimensional projector |ψS⟩⟨ψS|.
There is no degeneracy for modes in Figure 3a, but since the third and fifth modes are degenerate, in Figure 3b four modes are plotted.
end{aligned} (52) Note that Eq. (52) assumes that there is no degeneracy in the spectrum of Γ at zero order (as we will see, this is indeed the case).
Similar(51)
No apparent degeneracy is present between (c _{text{vis}}^{2}) and the remaining parameters, since (c _{text{vis}}^{2}) is weakly constrained for the neutrino parameters by the current data at the 95% confidence level.
However, by using the Ljusternik-Schnirelmann category no non-degeneracy condition is required.
However, in this case, if we assume no non-degeneracy conditions then the exponent (delta ) in the estimates (5.11) and (5.18) depends on the smoothness and if we assume a non-degeneracy condition (5.13) or (5.20) then obviously K depends on the smoothness.
end{aligned} (2.50 One can easily see that begin{aligned} |nabla gamma |le frac{1}{2},quad rho gamma ge h, end{aligned} (2.51) ((2.45)_{1,2}) are fulfilled and either (|V| ge epsilon rho ^2) or (rho gamma asymp h) and therefore (2.48) holds ((hbar asymp 1) as (rho gamma asymp h) and no non-degeneracy condition is needed).
To distinguish M degenerate modes requires running at least M different simulations, so the computational effort is proportional to the size of the degeneracy, no matter how closely-spaced the modes; however, from those M simulations many other non-degenerate modes can also be extracted with high accuracy, without much extra effort.
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